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# Clausius-Clapeyron Equation Calculator

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## Clausius-Clapeyron Equation

The Clausius-Clapeyron Equation enables us to estimate the vapor pressure at another temperature if the vapor pressure is called at some point of temperature. The relationship between the temperature of a liquid and its vapor pressure is not a straight line.

### Clausius-Clapeyron Equation Calculator

Clausius-Clapeyron Equation is used to resolve the vapor pressure of given liquid or solids.

## Clausius-Clapeyron Equation Calculator

 Initial Temperature(T1): Grams Final Temperature(T2): atm Vapor Pressure at Temperature T1 (P1): atm Vapor Pressure at Temperature T2 (P2): atm The Molar Enthalpy of Vaporization (Δ Hvap) = mole/m3

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In ( P1)/P2 =(∆Hvap/ R )(1/(T2 )-1/T1)

Where, P1 and P2 are the initial and final pressures,

T1 and T2 are the initial and final temperatures,

Hvap is enthalpy of vaporization

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Clausius Clapeyron Equation Calculator calculates the molar enthalpy of vaporization Hvap if initial pressure P1, final pressure P2, initial temperature T1 and final temperature T2.

### Methods for Clausius Clapeyron Equation Calculator

Step 1:

Firstly, read the problem and observe the given quantities.

Step 2:

Use the formula:

∆Hvap=(Rln P2/P1)/(1/T1-1/T2)

Where P1 and P2 are the initial and final pressures,

T1 and T2 are the initial and final temperatures,

Hvap is enthalpy of vaporization.

Substitute the given quantities to get the desired quantity.

## Problems on Clausius Clapeyron Equation Calculator

Find the Enthalpy of vaporization if the Vapor pressures of ice at 270 and 275K are 1.56 pa and 3.780 pa respectively?

Step 1:  Given quantities are:

Initial pressure p1 = 1.56 pa

Final pressure p2 = 3.78 pa

Initial temperature T1 = 270 K,

Final temperature T2 = 275 K.

Find Molar enthalpy of vaporization Δ Hvap.

Step 2:  To Molar enthalpy of vaporization is given as:

Δ Hvap = (Rln p2/p1)/(1/T1-1/T2)
= R ln p1/p2 T1T2/(T2-T1)
= 8.314 × ln 1.56/(3.78 )×(270×275)/(275-270)
= (-7.358)/(-0.0000673 )

= 109334.43 J/mol.

Answer:

Therefore, the Enthalpy of Vaporization Δ Hvap = 109334.43 J/mol.